Question

2. Factorise.
(1) 4p2-992
(ii) 63a2 - 1126
(iii) 49x? - 36​

Answer 1

Answer:

4p2−9q2

=(2p)2−(3q)2 

=(2p+3q)(2p−3q)

(ii) 63a2−112b2

=7[(3a)2−(4b)2]

=7(3a+4b)(3a−4b)

(iii) 49x2−36

=[(7x)2−(6)2]

 =(7x−6)(7x+6)

(iv) 16x5−144x3

=16x3[x2−32]   

=16x3(x−3)(x+3)

(v) (l+m)2−(l−m)2 

=2m×2l=4lm

(vi) 9x2y2−16

=[(3xy)2−42] 

=(3xy−