Question

2) Find a point on Y-axis which is equidistant from the point A(6,5) and B(-4,3) Solution : A( 6, 5) and B(-4, 3) Let P(0, y) be the point on Y-axis which is equidistant from A(6,5) and B (-4, 3) PA = PB PA2=PB2 Using distance formula. (6-0)2 + (O)2 = (O)2 + ( 3 - y)2 2 + 36+ 25 + y2 -10y=0 36 + 25 - 16 - 9 = 10y - 6y 4y = 36; Hence the required point is (O) ---​

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