Question

2. Find a polynomial whose zeros are 9 and 1/9​

Answer 1

Answer:

x^2 - 82x/9 + 1

Step-by-step explanation:

α = 9 ; β = 1/9

Sum of zeroes(s) = 9 + 1/9 = 82/9

Product of zeroes(p) = 9 x 1/9 = 1

The polynomial expression would be

x^2 - x(s) + (p)

= x^2 - 82x/9 + 1

Hope I helped

Answer 2

hey mate

given here

zeros of polynomial

9 and. 1/9

so,

sum of zeros = 9+ 1/9

=82/9

product of zeros = 9×1/9

=1.

formula of polynomial.

x^2-(sum of zeros )x+(product of zeros)=0

x^2-(82/9)x+(1)=0

I hopes its helps u

@abhi.