2. Find angles x and y in figure:
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I hope this may help....... and just remember it's a right angled isosceles triangle, thus the opposite sides are equal -thanks-
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<1 + y = 180° eq(1). (linear pair of angles)
<1 = x eq(2). (opposite angles of equal sides of a triangle)
by eq(1) and (2)
x + y = 180° eq(3)
In ∆PQR,
x + <1 + 90° = 180°. (angle sum property of ∆)
x + x = 90°
2x = 90°
x = 45°
and, x + y = 180°
45° + y = 180°
y = 180° - 45°
y = 135°
so, x = 45°
y = 135°
(kindly refer to attachment also)
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