Question

2. Find how many two-digit numbers are divisible by 6.​

Answer 1

Answer:

To find two digit numbers that are divisible by 6

By Divisibility rule,

6 is a multiple of 2 and 3.

Thus it has two combination to test ie; Test for 2 and Test for 3.

The first two digit number divisible by 6 is 12  and

The last two digit divisible by 6 is 96

Let a=12 , d=6,  an=96

Now we have

an=a+(n-1)d

=>96=12+(n-1)6

=>96-12=(n-1)6

=>84=(n-1)6

=>n-1=84 / 6

=>n-1=14

=>n=14+1

=>n=15

Hence total number of two digit number divisible by 6 = 15.

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Answer 2

hey mate

here is your answer

first two digit no. divisible by 6 is 12

and last two digit no. divisible by 6 is 96

the AP goes like

12,18,24,......,96

a=12,d=6

an=96

an=a+(n-1)d

96=12+(n-1)6

84=6n-6

90=6n

n=15

15 two digit no.s are divisible by 6.

hope it helps u :)