Question

2. Find p(0),p(1) and p(2) for each of the following polynomials.
(1) p(x) = x2-x+1 1,1,3
(i) p ) = 2 + y + 2y2 - y
(iv) p(t) = (t - 1) (t + 1)
(v) p(x) = x² – 3x + 2
(ii) p(z) =23​

Answer 1

Step-by-step explanation:

1.p(x)=x²-x+1

p(0)=0²-0+1

=0-0+1

=1

p(1)=1²-1+1

=1-1+1

=1-0=1

p(2)=2²-2+1

=4-2+1

=4-1=3