Question

Factorise:
2x^3-4x^2+3x-6-2xy+4y​

Answer 1

Answer:

helo friends its your answer

Step-by-step explanation:

NCERT Solutions(1)

(vi) 16x3, –4x2, 32x. (vii) 10pq, 20qr, 30rp ... (iv ) 2x = 2 × x. 3x2 = 3 × x × x. 4 = 2 × 2. The common factor is 1. ... + 5b + 2. (ix) 6xy – 4y + 6 – 9x ... (iii) 2x3 + 2xy2 + 2xz2 = 2x(x2 + y2 + z2) (2) -2x^3-4x^2-3x-6 | Mathway

Algebra. Factor -2x^3-4x^2-3x-6. −2x3−4x2 −3x−6 - 2 x 3 - 4 x 2 - 3 x - 6. Factor −1 - 1 out of −2x3−4x2−3x−6 - 2 x 3 - 4 x 2 - 3 x - 6

Answer 2

To Facotrise :

• $\large\underline{\bf{ \red{ {2x}^{3} - {4x}^{2} + 3x - 6 - 2xy + 4y}}}$

Solution

$\sf \: 2x³-4x²+ 3x-6-2xy +4y$

$\sf = (2x³-4x²)+(3x-6)-(2xy-y)$

$\sf = 2x²(x-2)+3(x-2)-2y(x-2)$

$\sf=(x-2)(2x²-2y+3)$