Question

2. Find p(0),p(1) and p(2) for each of the following polynomials.
(1) p(x) = x2- x +1
(i) ply)= 2 + y + 2y- y
(ii) p(z)=2
(iv) p(t) = (t - 1) (t+1)
(v) p(x) = x2 – 3x + 2​

Answer 1

if p(0) then p(X) = (0)² - 0+1 = 1

p(y) = 2+0+2(0)-0 = 2

p(t) = (0-1)(0+1)= -1×1 = -1

p(X) = 0²-3(0)+2 = 2

If p(1) then p(X) = (1)²-1+1 = 1

p(X) 2+1+2-1 = 4

similarly , the other numbers can be solved.