Question

2. Find the 30th term of AP series 10, 7.4.
​

Answer 1

Answer:

-77

Step-by-step explanation:

nth term of an AP is given by

tn =a+(n−1)d

In the given sequence, 'a' = 10, 'd' = -3, 'n' = 30.

So, 30th term =

‎ ‎ ‎ ‎ ‎ ‎ ‎‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎t30 =10+(30−1)(−3)

$\implies t30=10−87=−77.$