2. Find the amount from the investment of 4,500 for two years at 5 paise per
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Answer:
Step-by-step explanation:
\begin{gathered} Principal (P)=Rs\:4500,\\Rate\:of\: interest (r)=5\%,\\Time(T)=2\: years,\\Let,\:the \: Amount = A\end{gathered}
Principal(P)=Rs4500,
Rateofinterest(r)=5%,
Time(T)=2years,
Let,theAmount=A
\boxed {A=P\left(1+\frac{RT}{100}\right)}
A=P(1+
100
RT
)
\begin{gathered}\implies A = 4500\left(1+\frac{5\times 2}{100}\right)\\=4500\left(1+\frac{1}{10}\right)\\=4500\times \left(\frac{10+1}{10}\right)\\=4500\times \frac{11}{10}\\=450\times 11\\=Rs\:4950\end{gathered}
⟹A=4500(1+
100
5×2
)
=4500(1+
10
1
)
=4500×(
10
10+1
)
=4500×
10
11
=450×11
=Rs4950
Therefore,
Amount (A)=Rs\:4950Amount(A)=Rs4950
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