Question

2. Find the amount of Rs. 1, 25,000 after 3 years, when the interest is compounded annually at the rate of 6% per annum​

Answer 1

Answer:

p=125000

n=3

r=6%

amount=p(1+r/100)n

amount=125000(1+6/100)³

amount=148877

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Answer 2

Answer:

23877

Step-by-step explanation:

⇒  A=P[1+ r/ 100  ]  n

⇒  A=Rs.125,000×( 106/ 100  )  ^3

⇒  125,000×  53/50  x  53/50 x 53/50

⇒  A=Rs.148877

⇒  CI=A−P

⇒  Rs.148877−Rs.125,000

∴   CompoundInterest=Rs23877