Question

2. Find the area of a cardboard required to make a closed tea box of dimensions 10 cm ×8cm×6cm​

Answer 1

We know that TSA of a cuboidal shape is

2( l,b + b.h + l.h )

Therefore

Cardboard required will be

2 ( 10 * 8 + 8 * 6 + 6 * 10 ) cm square

= 2 ( 80 + 48 + 60 ) cm square

= 2 * 188 cm square

= 376 cm square

Answer 2

Step-by-step explanation:

2(lb+bh+lh)= 2(10×8+8×6+6×10)

2(80+48+60)

2×188

375 cm2