2. Find the area of the shaded region in fig. 8, if ABCD is
a square of side 14 em and APD and BPC are
semicircles
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Answer:
Total area of square= 14²= 196 cm²
Now, area of two semicircles....
= 2 × 1/2× πr²
after simplifying,
= πr²
=22/7× 7² [ r= 1/2 of square side because it's also the diameter of circle]
= 154 cm²
Now area of the shaded region,
= ar of square- ar of two semicircles
= 196-154
=42 cm² is the area of shaded region...
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