Question

2. Find the area of the triangle whose vertices are (-3, 5), (5, 6) and (5,-2)​

Answer 1

Answer:

If area of triangle with vertices P(x1, y1), Q(x2, y2) and R(x3, y3) is zero, then (1/2) [x1 (y2 – y3 ) + x2 (y3 – y1 ) + x3(y1 – y2)] = 0 and the points P(x1, y1), Q(x2, y2) and R(x3, y3)are collinear.