Math, asked by kiranmishra21241, 4 months ago

2. Find the compound interest to the nearest rupee
on 10,800 for 21/2 years at 10% per annum.

Answers

Answered by supriyaverma80

0

Answer:

10800(1+10/200)⁵/²*² 1080*(21/20)*⁵ 13783.84. to nearest rupee is 13784 (approx)

Step-by-step explanation:

thanks..

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