Question

2. Find the difference between the compound interest compounded yearly and half-yearly on 10,000 for 18 months at 10% per annum.​

Answer 1

Given: p = Rs 10,000; n = 18 months = 1

2

1

​

year and r = 10% p.a.

For 1 year

A=P(1+

100

r

​

)

n

=10,000(1+

100

10

​

)

1

=10,000(

10

11

​

)

1

=Rs. 11,000

For 1/2 year

P = Rs. 11,000; n = 1/2 year and r = 10%

A=P(1+

2×100

r

​

)

n×2

=11,000(1+

2×100

10

​

)

2

1

​

×2

=11,000(

20

21

​

)

1

=Rs. 11,550

∴ C.I. = Rs. 11,550 - Rs 10,000 = Rs, 1,550

(ii) When interest is compounded half-yearly

P = Rs. 10,000; n = 1

2

1

​

year and r = 10% p.a.

A=P(1+

2×100

r

​

)

n×2

=10,000(1+

2×100

10

​

)

2

3

​

×2

=10,000(

20

21

​

)

3

=Rs. 11,576.25

∴ C.I. = Rs 11,576.25 - Rs 10,000 = Rs 1,576.25

∴ Difference between both C.I. = Rs 1,576.25 - Rs 1,550 = Rs. 26.25

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Answer 2

Step-by-step explanation:

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