Question

2. Find the equations of tangents to the hyperbola y?
=1 which are parallel to 10x-3y+9=0,
16 64
​

Answer 1

Answer:

(x2/16) - (y2/64) = 1 Here a2 = 16 and b2 = 64 The equation of tangents will be of the form y = mx ± √(a2m2 - b2) (i.e.,) y = mx ± √(16m2 - 64) Where ‘m’ is the slope of the tangent. Here we are given that the tangents are parallel to 10x – 3y + 9 = 0 So slope of tangents will be equation to slope of the given lineRead more on Sarthaks.com - https://www.sarthaks.com/872959/find-the-equations-of-tangents-to-the-hyperbola-x-2-16-y-2-64-1-which-are-parallel-to-10x-3y-9-0

Answer 2

Answer:

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