Math, asked by 1238853, 10 months ago

2. Find the following products.
(i) (13ax - 4) (5ay + 1)​

Answers

Answered by vaishnavitiwari1041
3

Answer:

Here's your answer

13ax(5ay + 1) - 4(5ay + 1) \\  \\  = 65 {a}^{2} xy + 13ax - 20ay - 4

Hope it helps

Answered by Anonymous
3

Answer:

\large{(13ax-4)(5ay+1)}

65a {}^{2} xy + 13ay - 20ay - 4

65a {}^{2} xy  - 7ay - 4

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