Question

2.
Find the HCF of the following numbers by prime factorisation method.
a) 150.405
b) 390,468​

Answer 1

Answer:

A) 150=5×3×2×5

405=5×3×3×3×3

HCF = 5×3= 15

b)390=13×5×2×2

468=2×2×3×3×13

HCF =13×2×2=52