Question

2. Find the measure of each angle of
a parallelogram, if s angle as 24 less
than the twice of the smallest
angle.
​

Answer 1

let the smallest angle be x

then other larger angle is

2x-24

sum of all angle is 360

hence , 2x+2(2x-24)=360

6x=360+48

x=68

hence angles are 68,68, 112,112