Question

2.
Find the number which when increased by 12% of itself is 896.
TT
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Answer 1

$\huge\purple{\boxed{\boxed{\bigstar{\mathfrak{Answer}}}}}$

let the number be X

12% of X+12%=896

$\frac{12}{100} \times \frac{x}{1} + \frac{12}{100} = 896$

$\implies \frac{12}{100} \times \frac{x}{1} \frac{ \times }{ \times } \frac{100}{100} + \frac{12}{100} = 896$

$\implies \frac{12x}{100} \times \frac{100 + 12}{100} = 896$

$\implies \frac{12x}{100} \times \frac{112}{100} = 896$

$\implies \frac{12x}{100} = 896 \times \frac{100}{112}$

$\implies \frac{12x}{100} = 448 \times \frac{100}{56} \\ \implies \frac{12x}{100} = 224 \times \frac{100}{28} \\ \implies \frac{12x}{100} = 224 \times \frac{100}{28}$

$\implies \frac{12x}{100} = 224 \times \frac{50}{14} \\ \implies \frac{12x}{100} = 16 \times 50$

$\implies \frac{12x}{100} = 800 \\ \implies \: x = 800 \times \frac{100}{12}$

$\implies \: x = 400 \times \frac{100}{6} \\ \implies \: x = 200 \times \frac{100}{3}$

$\implies \: x \: = 6666.6666667 \\ hope \: this \: helps \: u$

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