2) Find the perimeter of rectangle of
a) It's length is double
b) It's length and breadth is triple .
Note - ( with proper solution )
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Answer:
0000000Step-by-step explanation:
\begin{gathered}a {}^{4} - 2a {}^{2} b {}^{2} + b {}^{4} = 0 \\ (a {}^{2} - b {}^{2} ) {}^{2} { = 0} \\ (a {}^{2} - b {}^{2} ) (a {}^{2} - b {}^{2} ) = 0\end{gathered}
a
4
−2a
2
b
2
+b
4
=0
(a
2
−b
2
)
2
=0
(a
2
−b
2
)(a
2
−b
2
)=0
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a) Perimeter increases by a magnitude twice that of initial length
b) If the length and breadth of a rectangle are trebled. ... Thus, the area of the rectangle will become 2 times that of its original area.
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