Question

2. Find the perimeter of the rectangle, whose length and breadth are respectively.(i) 5 cm and 15 cm(ii) 112 cm and 84 cm(iii) 30 cm and 20 cm(iv) 289 cm and 111 cm(v) 47 m and 23 m(vi) 27 m and 32 m

Answer 1

Answer :

• 40cm
• 392cm
• 100cm
• 800cm
• 140cm
• 118cm

To find :

• Perimeter of rectangle

Solution :

(1) 5cm and 15cm

• Length = 5cm
• Breadth = 15cm

As we know that ,

• Perimeter of rectangle = 2(l + b)

Where, l is length and b is breadth

》Perimeter of rectangle= 2(l + b)

》2(5 + 15)

》2(20)

》40cm

Hence, Perimeter of rectangle is 40cm

(2) 112cm and 84cm

• Length = 112cm
• Breadth = 84cm

As we know that ,

• Perimeter of rectangle = 2(l + b)

Where , l is length and b is breadth

》2(l+ b)

》2(112 + 84)

》2(196)

》392cm

Hence , Perimeter of rectangle is 392cm

(3) 30cm and 20cm

• Length = 30cm
• Breadth = 20cm

As we know that,

• Perimeter of rectangle = 2(l + b)

》2(l + b)

》2(30 + 20)

》2(50)

》100cm

Hence, Perimeter of rectangle is 100cm

(4) 289cm and 111cm

• Length = 289cm
• Breadth = 111cm

As we know that,

• Perimeter of rectangle = 2(l + b)

》2(l + b)

》2(289 + 111)

》2(400)

》800cm

Hence , Perimeter of rectangle is 800cm

(5) 47m and 23m

• Length = 47m
• Breadth = 23m

As we know that,

• Perimeter of rectangle = 2(l + b)

》2(l + b)

》2(47 + 23)

》2(70)

》140m

Hence , Perimeter of rectangle is 140m

(6) 27m and 32m

• Length = 27m
• Breadth = 32m

As we know that,

• Perimeter of rectangle = 2(l + b)

》2(l + b)

》2(27 + 32)

》2(59)

》118m

Hence , Perimeter of rectangle is 118m

Answer 2

$\boxed{\tt{\underline{Solution \: 1:-}}}$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( length \: + \: breadth) }$

• Length = 5cm
• Breadth = 15cm

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( 5\: + \: 15) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( 20) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2 \: \times \: 20 \: }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:40cm\: }$

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$\boxed{\tt{\underline{Solution \: 2:-}}}$

• Length = 112 cm
• Breadth = 84 cm

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( length \: + \: breadth) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( 112 \: + \: 84) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( 196) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2 \: \times \: 196}$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:392cm}$

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$\boxed{\tt{\underline{Solution \: 3:-}}}$

• Length = 30cm
• Breadth = 20cm

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( length \: + \: breadth) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( 30 \: + \: 20) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( 50) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2 \: \times \: 50 }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \: 100cm}$

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$\boxed{\tt{\underline{Solution \: 4:-}}}$

• Length = 289cm
• Breadth = 111 cm

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( length \: + \: breadth) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( 289 \: + \: 111) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( 400) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2 \: \times \: 400}$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:800cm }$

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$\boxed{\tt{\underline{Solution \: 5:-}}}$

• Length = 47m
• Breadth = 23m

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( length \: + \: breadth) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( 47\: + \: 23) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( 70) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2 \: \times \: 70 }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:140m }$

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$\boxed{\tt{\underline{Solution \: 6:-}}}$

• Length =  27 m
• Breadth =  32 m

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( length \: + \: breadth) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( 27 \: + \: 32) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2( 59) }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:2 \: \times \: 59 }$

$\sf{ \longmapsto \: perimeter \: of \: the \: rectangle \: = \:118m }$

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