Question

2. Find the point on the x-axis, which is
equidistant from the points (3, 4) and (1. - 3).​

Answer 1

Answer:

Distance formula=(x2-x1)^2+(y2-y1)^2

Point on x axis=x

Y axis =0

(x,0)

(3,4) (1,-3)

(x2-x1)^2+(y2-y1)^2=(x2-x1)^2+(y2-y1)^2

(x-3)^2+(0-4)^2=(x-1)+(0-3)

x^2-6x+9-4^2=x^2-2x+1-3^2

x^2-6x+9-16=x^2-2x+1-9

x^2-6x-7=x^2-2x-8

-6x-7= -2x-8

-7+8= -2x+6x

1=4x

x=1/4