Math, asked by peteraswin3, 4 months ago

find the standerd deviations and the variance of first 23 of natural number​

Answers

Answered by Anonymous
2

Answer:

Variance of first n natural numbers is given by

Variance=

n

∑n

2

−(

n

∑n

)

2

=

6n

n(n+1)(2n+1)

−(

2n

n(n+1)

)

2

=(n+1)[

6

2n+1

4

(n+1)

]

=

12

(n+1)

[4n+2−3n−3]

=

12

(n+1)

×(n−1).

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