Question

2) Find the pressure at a depth of 100 m below the surface of a lake taking density of water = 1000 kg/m3. The atmospheric pressure being neglected​

Answer 1

Explanation:

The quantity of water in a column at a depth of 100 m below the surface with a base area 1 m² is 100 m³.

The mass of this column of water is 100 × 1000 = 100000 kg.

⇒ The pressure due to the column of water at a depth of 100 m below the surface of the sea is 100000 kgf/m² = 980.665 kPa.

⇒ The pressure at a point 100 m below the surface of the sea is = 980.665 kPa.