2) Find the pressure at a depth of 100 m below the surface of a lake taking density of water = 1000 kg/m3. The atmospheric pressure being neglected
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Explanation:
The quantity of water in a column at a depth of 100 m below the surface with a base area 1 m² is 100 m³.
The mass of this column of water is 100 × 1000 = 100000 kg.
⇒ The pressure due to the column of water at a depth of 100 m below the surface of the sea is 100000 kgf/m² = 980.665 kPa.
⇒ The pressure at a point 100 m below the surface of the sea is = 980.665 kPa.
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