Physics, asked by rithwik68, 7 months ago

2) Find the pressure at a depth of 100 m below the surface of a lake taking density of water = 1000 kg/m3. The atmospheric pressure being neglected​

Answers

Answered by Sajidh2004
19

Explanation:

The quantity of water in a column at a depth of 100 m below the surface with a base area 1 m² is 100 m³.

The mass of this column of water is 100 × 1000 = 100000 kg.

⇒ The pressure due to the column of water at a depth of 100 m below the surface of the sea is 100000 kgf/m² = 980.665 kPa.

⇒ The pressure at a point 100 m below the surface of the sea is = 980.665 kPa.

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