Physics, asked by rithwik68, 6 months ago

2) Find the pressure at a depth of 100 m below the surface of a lake taking density of water = 1000 kg/m3. The atmospheric pressure being neglected​

Answers

Answered by Anonymous
8

Explanation:

Given : h=10m, ρ=1000kg/m^3

, g=10m/s^2

Pressure on swimmer = pressure of atmosphere + pressure of water

=1atm+ρgh×10^−5atm

=1atm+1000×10×10×10^−5atm

=2atm

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