2) Find the pressure at a depth of 100 m below the surface of a lake taking density of water = 1000 kg/m3. The atmospheric pressure being neglected
Answers
Answered by
8
Explanation:
Given : h=10m, ρ=1000kg/m^3
, g=10m/s^2
Pressure on swimmer = pressure of atmosphere + pressure of water
=1atm+ρgh×10^−5atm
=1atm+1000×10×10×10^−5atm
=2atm
please mark as brainlist answer and follow me please thank answer
Similar questions