Question

2) Find the roots of the equation
2x²-x+ 1/8 = 0
fast answer
no spam pls ​

Answer 1

Step-by-step explanation:

given 2x^2-x+1/8=0

simplify the eq by multiplying the 8 on both side

= 8×2x^2-8x+1/8×8=0×8

= 16x^2-8x+1=0

solving the above eq by splitting middle term

= 16x^2-4x-4x+1=0

4x(4x-1) -1(4x-1) =0

(4x-1)(4x-1) =0

so x = 1/4, 1/4