Math, asked by yogesh1013, 11 months ago

2. Find the smallest number which leaves remainders 8 and 12 when divided by 28 and 32
respectively

Answers

Answered by bharath0719

1

Answer:

8 =2power3*1

12. =2²*3

LCM=2power3*3

=24

28. =2²*7

32. =2power5*1

LCM=2power5*7

=224

The smallest number is

224+24=248

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