Math, asked by StarTbia, 1 year ago

2. Find the square root of the following:

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Answers

Answered by rohitkumargupta
0
HELLO DEAR,



(x² - 25)(x² + 8x + 15)(x² - 2x - 15)

(x - 5)(x + 5)(x² + 5x + 3x + 15)(x² - 5x + 3x - 15)

(x - 5)(x + 5)(x + 5)(x + 3)(x - 5)(x + 3)

(x + 5)²(x - 5)²(x + 3)²
now the Square of the given no. Is

(x + 5)(x - 5)(x + 3)

(x² - 25)(x + 3)


I HOPE ITS HELP YOU DEAR,
THANKS
Answered by mysticd
0

Solution :


i ) x² - 25


= x² - 5²


= ( x + 5 )( x - 5 ) ----( 1 )


ii ) x² + 8x + 15


= x² + 5x + 3x + 15


= x( x + 5 ) + 3 ( x + 5 )


= ( x + 5 )( x + 3 ) ----( 2 )


iii ) x² - 2x - 15


= x² - 5x + 3x - 15


= x( x - 5 ) + 3 ( x - 5 )


= ( x - 5 )( x + 3 ) ----- ( 3 )


Now ,


√[(x²-25)(x²+8x+15)(x²-2x-15)]


= √[(x+5)(x-5)(x+5)(x+3)(x-5)(x+3)]


= √[(x-5)²(x+3)²(x+5)²]


= ( x - 5 ) ( x + 3 )( x + 5 )


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