Question

2.) Find the value of the polynomial 2x^³ x 3x^²+4x-1 at
(i) x = 0
(ii) x = 1
(iii) x = 2​

Answer 1

Answer:

i.0

ii.9

iii.199

Step-by-step explanation:

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Answer 2

• x = 0

$\implies$ 2x³ - 3x² + 4x - 1

$\implies$ 2 (0)³ - 3 (0)² + 4 (0) - 1

$\implies$ 2 (0) - 3 (0) + 0 - 1

$\implies$ 0 - 0 + 0 - 1

$\implies$ - 1

Therefore, the value of 2x³ - 3x² + 4x - 1 is - 1 when x = 0.

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• x = 1

$\implies$ 2x³ - 3x² + 4x - 1

$\implies$ 2 (1)³ - 3 (1)² + 4 (1) - 1

$\implies$ 2 (1) - 3(1) + 4(1) - 1

$\implies$ 2 - 3 + 4 - 1

$\implies$ - 1 + 3

$\longrightarrow$ 2

Therefore, the value of 2x³ - 3x² + 4x - 1 is 2 when x = 1.

_____________________

• x = 2

$\implies$ 2x³ - 3x² + 4x - 1

$\implies$ 2 (2)³ - 3(2)² + 4 (2) - 1

$\implies$ 2 (8) - 3 (4) + 8 - 1

$\implies$ 16 - 12 + 7

$\implies$ 4 + 7

$\implies$ 11

Therefore, the value of 2x³ - 3x² + 4x - 1 is 11 when x = 2.