Question

(2) Find the zeroes of 4x^2+8x and also
write the relation between zeroes and its
co-efficient. (3 marks) *​

Answer 1

Given quadratic equation is

→ 4x² + 8x = 0

→ 4x(x + 2) = 0

So, 4x = 0 OR (x + 2) = 0

Hence, it's zeroes are 0 & -2

Now, relation between zeroes and it's coefficients is

General form of quadratic is

ax² + bx + c = 0

Here, a = 4 ; b = 8 ; c = 0

Now, sum of zeroes = -b/a

→ -2 + 0 = -8/4

→ -2 = -2 (TRUE)

And, Product of zeroes = c/a

→ -2 x 0 = 0/8

→ 0 = 0 (TRUE)

Hope it helps....

^___^