Question

2. Find the zeros of the polynomial x2 + x-p(p+1).
[CBSE 2011]
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Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Thus,

zeroes are p and - (p+1)

Step-by-step explanation:

$x {}^{2} + x - p(p + 1)$

$= x {}^{2} + (p + 1)x - px \: - p(p + 1)$

$= x(x + p + 1) - p(x + p + 1)$

$= (x - p)(x + p + 1)$

Either (x-p) =0 or (x+p+1)=0

so, x= p, -(p+1)