Question

(2) For each of the following polynomial, find p(1), p(0) and p(- 2
fii) p(y) = y2 - 2y + 5 ​

Answer 1

Answer:

Give polynomial y²-2y+5

If p = 1

(1)²-2(1)+5

1-2+5

4

If p = 0

(0)²-2(0)+5

0-0+5

5

If p = -2

(-2)²-2(-2)+5

4+4+5

14

Step-by-step explanation:

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Answer 2

Answer:

It's 5 , 5, -3

Step-by-step explanation:

p(y) = y2 - 2y + 5

p(1) = 1*2-2*1+5

= 2-2+5

= 5

p(0)= 0*2-2*0+5

= 0-0+5

= 5

p(-2)= (-2)*2-2*(-2)+5

= -4-4+5

= -8+5

= -3