Question

2) For each of the following polynomial, find p(1), p(0) and p(-2).
(i) p(x) = x³
(ii) p(y) = y² - 2y + 5 (iii) p(x) = x⁴ - 2x² - x.​

Answer 1

Answer:

( i ) p(1)=(1)³

= 1

p(0)=(0)³

=0

p(-2)=(-2)³

=-8

(ii) p(1)= (1)²-2(1)+5

1-2+5

=4

p(0)=(0)²-2(0)+5

0-0+5

=5

p(-2)=(-2)-2(-2)+5

=7

(iii) p(0)=(0)⁴-2(0)²-0

0

p(1)= (1)⁴-2(1)²-1

1-2-1

=-2

p(-2)=(-2)⁴-2(-2)²-(-2)

-16-8+2

=-22