Question

2) Frame the polynomial whose zeroes are sin30° and coso​

Answer 1

Step-by-step explanation:

sin30=1/2

cos0=1 OK friend this is urs answer

Answer 2

We have to find such an polynomial of roots are sin 30 and cos 30 that means whose roots are

\frac{1}{2} \: and \: \frac{ \sqrt{3} }{2}

Sum \: of \: roots (s)= \frac{1 + \sqrt{3} }{2}

Product \: of \: roots(p) = \frac{ \sqrt{3} }{4}

As we know that form of an polynomial whose product of roots and sum of roots are given will be

{x}^{2} - sx + p

So by putting values of s and p we get the polynomial is:-

{x}^{2} - (\frac{1 + \sqrt{3} }{2} )x + \frac{ \sqrt{3} }{4} </p><p>

Above polynomial is required polynomial whose roots are sin 30 and cos 30 .