Question

2
G/ A stone of 1 kg is thrown with a velocity of 20 ms across
the frozen surface of a lake and comes to rest after travelling
a distance of 50 m. What is the force of friction between the
stone and the ice?​

Answer 1

Answer:

4N

Explanation:

v^2 = u^2 + 2as

0 = 20^2 - 2*a*50

a = 4

F = ma = 1*4 = 4 N

Answer 2

Answer:

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