the sum of first n terms of an ap is 3 nsquare + 6n then find the nth term of this ap
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Answer:
6n + 3
Step-by-step explanation:
Tn = S n - S (n-1)
= 3n^2 + 6n - [3(n-1)^2 + 6(n-1)]
= 6n + 3
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