Question

2 g atom of A reacts with 2 g molecule of B4
according to following reaction
2A2(g) + 3B (g) → 4C
Correct statement is
1) A, will be the limiting reagent
2) BA will be the limiting reagent
3) 2 * No atom of C will be formed
4) Both (1) & (3)​

Answer 1

Answer:

4) is the correct option

Explanation:

From the question, 4 atoms of A requires 3 gram molecules of B4. so 2 g atoms require 2*3/4=1.5 So A is limiting reagent. 4C = 2A2+3B4. so C is AB3. so 2* Na atom of C will be formed.