Question

2 g of ice at 0°C is dropped in a beaker containing 10 g
of water at 20°C. The final temperature of the mixture
will be

10° C
10/3°C
5°C
14/3°C

please answer fast​

Answer 1

Given:

2 g of ice at 0°C is dropped in a beaker containing 10 g of water at 20°C.

To find:

Final temperature of mixture?

Calculation:

• Latent heat of fusion of ice is 80 Cal/g
• Specific heat capacity of water is 1 Cal/gK

Applying Principle of CALORIMETRY:

$\therefore \: energy \: taken \: up \: by \: ice = energy \: released \: by \: water$

$\implies \: (m1)L +( m1)c(\Delta \theta_{1}) = (m2)c(\Delta \theta_{2})$

$\implies \: (2 \times 80) + \{2 \times 1 \times ( \theta - 0) \}= \{10 \times 1(20 - \theta) \}$

$\implies \: 160 +2 \theta = 200 - 10 \theta$

$\implies \: 12 \theta = 40$

$\implies \:\theta = \dfrac{40}{12}$

$\implies \:\theta = { \dfrac{10}{3}}^{ \circ} \: C$

So, final temperature is (10/3)° C.