Question

2.
Given figure is a solid composed of a cylinder with a hemisphere on
the top. If the curved surface areas of hemisphere and cylinder are
50 cm and 75 cm respectively, find the curved surface area of the solid.
​

Answer 1

Answer:

Answer

For all figures,

r=7 cm

l (slant height)= h (height of cylinder)=4 cm

T.S.A of the figure= C.S.A of Cone+C.S.A of cylinder +C.S.A of hemisphere.

CSA of cone: πrl=(3.14)×(7cm)×(4cm)=87.92 cm

2

CSA of cylinder: 2πrh=(2)×(3.14)×(7cm)×(4cm)=175.84 cm

2

CSA of hemisphere: 2πr

2

=(2)×(3.14)×(7cm)

2

=307.72 cm

2

Adding all: TSA of figure= 571.48 cm

2

Answer 2

Answer:

571.48cm

Step-by-step explanation:

For all figures,

r=7 cm

l (slant height)= h (height of cylinder)=4 cm

T.S.A of the figure= C.S.A of Cone+C.S.A of cylinder +C.S.A of hemisphere.

CSA of cone: πrl=(3.14)×(7cm)×(4cm)=87.92 cm

2

CSA of cylinder: 2πrh=(2)×(3.14)×(7cm)×(4cm)=175.84 cm

2

CSA of hemisphere: 2πr

2

=(2)×(3.14)×(7cm)

2

=307.72 cm

2

Adding all: TSA of figure= 571.48 cm

2