Peter throws two different dice together and finds the product of the two numbers obtained. Rina throws a die squares the number obtained. Who has the better chance to get the number 25
Answers
Answer:
Let us first write the all possible oucomes when Peter throws two different dice together.
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(5,3),(5,4),(5,5),(5,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
∴ Total number of outcomes =36
The favorable outcome for getting the product of numbers on the dice equalto 25 is (5,5) .
Favourable number of outcomes =1
∴ Probability that Peter gets the product of numbers as 25
=
Total number of outcomes
Favourable number of outcomes
=
36
1
The outcomes when Rina throws a die are 1,2,3,4,5,6
∴ Total number of outcomes =6
Rina throws a die and squares the number, so to get the number 25, the favourable outcome is
5.
Favourable number of outcomes = 1
Favourable number of outcomes = 1
∴ Probability that Rina gets the square of the number as 25
Total number of outcomes
Favourable number of outcomes
=
6
1
As, 1/6>1/36, so Rina has better chance to get the number 25 .
Answer:
rina
Step-by-step explanation:
for Peter , probability= 1 out of 36
for Rina , probability = 1 out of 6