Question

(2) . Given that: (1 + cosα) (1 + Cosβ) (1 + cosγ) = (1 - cosα)(1 – cosβ) (1 – cos γ) .Show that one of the values of each member of this equality is sinα sinβ sinγ. • Quality Answer Mark As Brainliest. • Spammers Stay Away!!.​

Answer 1

Explanation:

We have: (1+cosα)(1+cosβ)(1+cosγ)

(1−cosα)(1−cosβ)(1−cosγ)

Multiplying both sides by

(1+cosα)(1+cosβ)(1+cosγ), we get

(1+cosα)

2

(1+cosβ)

2

(1+cosγ)

2

(1−cosα)(1−cosβ)(1−cosγ)(1+cosα)(1+cosβ)(1+cosγ)

⇒(1+cosα)

2

(1+cosβ)

2

(1+cosγ)

2

=(1−cos

2

α)(1−cos

2

β)(1−cos

2

γ)

⇒(1+cosα)

2

(1+cosβ)

2

(1+cosγ)

2

=sin

2

αsin

2

βsin

2

γ

⇒(1+cosα)(1+cosβ)(1+cosγ)=±sinαsinβsinγ

Hence, one of the values of (1+cosα)(1+cosβ)(1+cosγ) is sinαsinβsinγ

Answer 2

Answer:

Refer to the attachment

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