Question

(-2-i1/3)3 find the value in the form of a+ib

Answer 1

the ans in a+ib is -22/3+i(-77/27)
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Answer 2

(a-b)^3=a^3-b^3-3a^2b+3ab^2

substituting a=-2,b=i1/3=i/3
also i^2= -1,i^3=i
(-2-i/3)^3=
(-2)^3-(i/3)^3-3(-2)^2(i/3) +3(-2)(i/3)^2
=8-(i/27)-(12i/3)+(4/9)
=8+(4/9)-[(i/27)+(12i/3)]
Taking LCM,
=(72+4)/9-[(i+84i)/27]
=76/9-85i/27

Hope this helps