plz it's urgent............ . plz don't do on paper..... thanks
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hey mate here is yr answer!!
1)x3-2x2-x+2
=arranging the terms we get,
x3-x-2x2+2
=x(x2-1)-2(x2+1)
but if we take minus as common then the singns are changed...
hence,x(x2-1)-2(x2-1)
=(x2-1)(x-2) ans...
4)y2(2y+1)-y(2y-1)
=y2(2y+1)-y(2y+1)
=(2y+1)(y2-y) Ans.
1)x3-2x2-x+2
=arranging the terms we get,
x3-x-2x2+2
=x(x2-1)-2(x2+1)
but if we take minus as common then the singns are changed...
hence,x(x2-1)-2(x2-1)
=(x2-1)(x-2) ans...
4)y2(2y+1)-y(2y-1)
=y2(2y+1)-y(2y+1)
=(2y+1)(y2-y) Ans.
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