Question

2. If (28) is the mean proportional of (23-x) and (19-x) then find the value of x.​

Answer 1

Answer:

idk bro i got stuck sorry

Step-by-step explanation:

(28)^2 = (23-x)*(19-x)

784 = (23*19)-23x-19x+$x^{2}$

784-437 = -42x+$x^{2}$

347/-42 = x+$x^{2}$

-8.2 = x+$x^{2}$

$\sqrt[2]{-8.2}$ = 2x

$\sqrt[2]{-8.2}$ /2 = x

x = 1.4

HOPEFULLY ITS CORRECT

MARK ME BRAINLIEST

SORRY IF ITS WRONG THO!!!