2] If 4, X1, X2 ,X3, and 28 are in AP, then x3, is
A] 18
B] 19
C] 22
D] 23
Answers
Answered by
6
Answer:
a=4 n=5 l=28 then an=a+(n-1)d
28= 4+4d
4d=24
d=6 then x3= 22 ok bro
I hope you it will be help
Answered by
4
Answer:
a=4,a5=28
a5=a+4d
28=4+4d
28=4(1+d)
7=1+d
d=6
x3=a4=a+3d=4+3(6)=4+18=22
[C] 22 is correct
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