2. If a car engine is having an efficiency of 70 %, how much fuel has to used to move the car with an acceleration of 2 m/s2 to a distance of 30 m. the mass of the car is 1500 kg. each litre of fuel produces 30*106 J of energy per second.
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Answer:
For a vehicle with mv = 1500 kg, Af · cd = 0.7 m2, cr = 0.012, a vehicle speed
v = 120 km/h and an acceleration a = 0.027 g, calculate the traction torque
required at the wheels and the corresponding rotational speed level (tires
195/65/15T). Calculate the road slope that is equivalent to that acceleration.
• Solution
Assume ρa = 1.20kg/m3, g = 9.81m/s2.
a) Traction torque required at wheels:
Ft = mv · cr · g + 1/2 · ρa · Af · cd · v2 + mv · a =
= 1500 · 0.012 · 9.81 +
1
2 · 1.2 · 0.7 ·
!120
3.6
"2
+ 1500 · 0.027 · 9.81 = 1041 N
The information about the tires is explained by
newline
195
#$%&
width of the
tire in [cm]
/ 65
#$%&
ratio of sidewall
height to tire
width in [%]
/ 15
#$%&
wheel diameter
in [inch]
T
#$%&
max. 190 [km/h]
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