Question

2. If current I = 32 A, t = 1s, calculate the
number of electrons per sec?​

Answer 1

Here ,

• I → 32A
• t → 1sec
• e → ${1.6×{10}^{-19}}$ C

To find :—

• Number of electrons (n)

We know that ,

$\large \bold{I = \frac{Q\:\:(charge)}{t}}$

$\bold{\implies32 = \frac{Q}{1} }$

$\bold{\implies \: Q = 32 \:C }$

Again we know that,

$\large \color{red}{\bold{Q = n e}}$

$\implies \: 32 \: = n \: \times 1.6 \times {10}^{ - 19}$

$\bold{ \implies \: n \: = \frac{32}{1.6 \times {10}^{ - 19} } }$

$\bold{ \implies \: n \: = {20 \times {10}^{19} }}$

$\bold{ \implies \: \boxed{\bold{n \: = {2 \times {10}^{20} }}}}$

So, number of electrons → 2 × 10²⁰