Question

2) If log 108 - log 176-log x +log 396 –log 81=0, then find the
value of 'x'.​

Answer 1

Step-by-step explanation:

$log(108) - log(176) + log(396) - log(81) = log(x)$

We know that

Log m*n =log m+ log n

Log108=log9 * 12=log 9+ log 12

Log81 =2log9

Log396=log 9 +log 44

Log176=log 4+log 44

So

log 9+log12-log 4 - log 44 +log 9 +log 44 - 2 log 9

= log 12-log4= log 4+log 3- log 4=

Log 3 = log x

Applying antilog

X=3

Answer 2

Answer:

here is the answer

ok

hope it helps you